: Consider the following recursive solution to compute the Levenshtein distance between two string. Note that tail (a) is the string without the first character
: Consider the following recursive solution to compute the Levenshtein distance between two string. Note that tail (a) is the string without the first character (a.substring (1)) and la| is the length of a (a.length ()). How
mamy times is the function called (in total) when computing Lev (‘HHE’, ‘HH#’)?
len(a)
len(b)
if len(b) = 0
if len(a) = 0
Lev(a,b) =
Lev( tail(a), tail(b))
if a[0] = b[0]
/ Lev( tail(a), b )
1 + min | Lev( a, tail(b) )
otherwise
\ Lev( tail(a), tail(b) )
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